The intersection of two lines refers to a point where two distinct lines in a plane meet or cross each other. This concept is fundamental in geometry and linear algebra. Each line can be represented by an equation, typically in the form $y = mx + b$ for lines in a two-dimensional plane, where $m$ is the slope of the line and $b$ is the y-intercept.
To find the intersection of two lines, their equations are set equal to each other, and this system of equations is solved to find the values of $x$ and $y$ that satisfy both equations simultaneously. The solution $(x, y)$ represents the coordinates of the intersection point.
To find the intersection of two lines, you typically follow these steps:
Write down the equations of the two lines. Generally, line equations are given in the form $y = mx + b$ or $Ax + By = C$, where $m$ is the slope and $b$ is the y-intercept.
Set the right-hand sides of the equations equal to each other. This is because at the point of intersection, both lines have the same $x$ and $y$ coordinates.
Solve the resulting equation for $x$ to find the $x$-coordinate of the intersection point.
Substitute the $x$-coordinate back into one of the original line equations to solve for $y$, giving you the $y$-coordinate of the intersection point.
Given Lines:
Step 1:Solve the second equation for $y$.
$y = 4 - x$
Step 2: Replace $y$ in the first equation with $4 - x$ and solve for $x$.
$3x - 2(4 - x) = 6 \Rightarrow 3x - 8 + 2x = 6 \Rightarrow 5x = 14 \Rightarrow x = \frac{14}{5}$
Step 3: Substitute $x = \frac{14}{5}$ back into the equation for $y$.
$y = 4 - \frac{14}{5} = \frac{20 - 14}{5} = \frac{6}{5}$
Intersection Point: $\left(\frac{14}{5}, \frac{6}{5}\right)$
Find the intersection of two lines by graphing the function.
$3x - 2y = 6$
$x + y = 4$
Intersection Point: $\left(\frac{14}{5}, \frac{6}{5}\right)$
Given Lines:
Step 1: Set the equations equal to each other to find $x$. $2x + 1 = -x + 5$
Step 2: Solve for $x$. $3x = 4 \Rightarrow x = \frac{4}{3}$
Step 3: Substitute $x$ back into one of the original equations.
$y = 2(\frac{4}{3}) + 1 = \frac{8}{3} + 1 = \frac{11}{3}$
Intersection Point: $\left(\frac{4}{3}, \frac{11}{3}\right)$
Find the intersection of two lines by graphing the function.
$y = 2x + 1$
$y = -x + 5$
Intersection Point: $\left(\frac{4}{3}, \frac{11}{3}\right)$
Given Lines:
Step 1: Rearrange Equations to Slope-Intercept Form ($y = mx + b$). For Line 1: $3x - 9 = 6y \Rightarrow y = \frac{1}{2}x - \frac{3}{2}$ For Line 2: $3x - 2 = 6y \Rightarrow y = \frac{1}{2}x - \frac{1}{3}$
Step 2: Compare Slopes and Intercepts. Both lines have a slope of $\frac{1}{2}$, but different y-intercepts, showing they are parallel.
Conclusion: No intersection.
Find the intersection of two lines by graphing the function.
$3x - 6y = 9$
$3x - 6y = 2$
Intersection Point: Parallel Lines, No intersection.
Given Lines:
Step 1: Manipulate the second equation to match the form of the first. $-2y + 4x = -10 \Rightarrow y - 2x = 5$
Step 2: Compare the equations. Both equations simplify to $y - 2x = 5$, which means they are the same line represented in identical forms.
Conclusion: These are coincident lines with an infinite number of points of intersection.
Find the intersection of two lines by graphing the function.
$y - 2x = 5$
$-2y + 4x = -10$
Intersection Point: Coincident lines, an infinite number of points of intersection.